(8^-3y^4/x^2y^6)^2

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Solution for (8^-3y^4/x^2y^6)^2 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(((8^-3*y^4)/(x^2))*y^6)^2 = 0

1/262144*x^-4*y^20 = 0 // : 1/262144*y^20

x^-4 = 0

x naleu017Cy do O

x belongs to the empty set

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